Q.If a cone has volume \(V\) cubic units, total surface area \(S\) square units, height \(h\) units, and base radius \(r\) units, then show that: \[ S = 2V\left(\frac{1}{h} + \frac{1}{r}\right) \]

Volume of the cone \(V = \pi r^2 h\) Total surface area \(S = 2\pi r(r + h)\) \(= 2 \times \pi \times r \times (r + h)\) \(= 2 \times \pi \times r \times (r + h) \times \frac{rh}{rh}\) \(= 2 \times \pi r^2 h \times \left(\frac{r + h}{rh}\right)\) \(= 2 \times \pi r^2 h \times \left(\frac{r}{rh} + \frac{h}{rh}\right)\) \(= 2V\left(\frac{1}{h} + \frac{1}{r}\right)\) [Proved]
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