Let 50% of A = 60% of B = \(\frac{4}{5}\) of C = \(k\) \(\therefore\) \(A \times \frac{50}{100} = B \times \frac{60}{100} = C \times \frac{4}{5} = k\) \(\therefore\) \(A = \frac{k \times 100}{50} = 2k\) \(B = \frac{k \times 100}{60} = \frac{5k}{3}\) \(C = \frac{k \times 5}{4} = \frac{5k}{4}\) \(\therefore\) A : B : C = \(2k : \frac{5k}{3} : \frac{5k}{4}\) = 24 : 20 : 15