Answer: C
OB=3 cm, OQ=5 cm
OB⊥PQ
From ∆OBQ, we get BQ\(^2\)=OQ\(^2\)-OB\(^2\)
=5\(^2\)-3\(^2\)=25-9=16
∴BQ=\(\sqrt{16}\)=4
∴PQ=4×2=8 cm
OB=3 cm, OQ=5 cm
OB⊥PQ
From ∆OBQ, we get BQ\(^2\)=OQ\(^2\)-OB\(^2\)
=5\(^2\)-3\(^2\)=25-9=16
∴BQ=\(\sqrt{16}\)=4
∴PQ=4×2=8 cm