Answer: B
Let the number to be added be \(x\). \(\therefore (6+x):(7+x) = (15+x):(17+x)\) Or, \(\cfrac{(6+x)}{(7+x)} = \cfrac{(15+x)}{(17+x)}\) Or, \((6+x)(17+x) = (7+x)(15+x)\) Or, \(102 + 6x + 17x + x^2 = 105 + 7x + 15x + x^2\) Or, \(23x + x^2 - 22x - x^2 = 105 - 102\) Or, \(x = 3\)
Let the number to be added be \(x\). \(\therefore (6+x):(7+x) = (15+x):(17+x)\) Or, \(\cfrac{(6+x)}{(7+x)} = \cfrac{(15+x)}{(17+x)}\) Or, \((6+x)(17+x) = (7+x)(15+x)\) Or, \(102 + 6x + 17x + x^2 = 105 + 7x + 15x + x^2\) Or, \(23x + x^2 - 22x - x^2 = 105 - 102\) Or, \(x = 3\)