Answer: A
∴ In right-angled triangle ∆OPQ, OQ² + PQ² = OP² [By Pythagoras' Theorem] i.e., 6² + 8² = OP² ⇒ OP² = 36 + 64 = 100 ⇒ OP = 10 ∴ The distance from the center of the circle to the external point = 10 cm
∴ In right-angled triangle ∆OPQ, OQ² + PQ² = OP² [By Pythagoras' Theorem] i.e., 6² + 8² = OP² ⇒ OP² = 36 + 64 = 100 ⇒ OP = 10 ∴ The distance from the center of the circle to the external point = 10 cm