Q.In a group of \(n\) numbers with an average of \(\bar{x}\), if the sum of the first \((n - 1)\) numbers is \(K\), then the \(n\)th number will be \((n - 1)\bar{x} + K\).

The statement is false.
Let the average of \(n\) numbers be \(\bar{x}\). \(\therefore\) The sum of the \(n\) numbers is \(n\bar{x}\). If the sum of the first \((n - 1)\) numbers is \(K\), then the \(n\)th number will be \(n\bar{x} - K\).
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