Two circles with centers A and B, each having a radius of 10 cm, intersect at points P and Q. PQ = 12 cm Line AB intersects PQ at point O. ∴ In triangle AOP, AP = 10 cm OP = PQ/2 = 12/2 cm = 6 cm ∴ AO = √(AP² − OP²) = √(10² − 6²) cm = √(100 − 36) cm = √64 cm = 8 cm ∴ AB = 2 × AO = 2 × 8 cm = 16 cm ∴ The distance between the centers of the two circles is 16 cm.