Q.Two identical circles, each with a radius of 10 cm, intersect each other, and the length of their common chord is 12 cm. Find the distance between the centers of the two circles.

Two circles with centers A and B, each having a radius of 10 cm, intersect at points P and Q. PQ = 12 cm Line AB intersects PQ at point O. ∴ In triangle AOP, AP = 10 cm OP = PQ/2 = 12/2 cm = 6 cm ∴ AO = √(AP² − OP²) = √(10² − 6²) cm = √(100 − 36) cm = √64 cm = 8 cm ∴ AB = 2 × AO = 2 × 8 cm = 16 cm ∴ The distance between the centers of the two circles is 16 cm.
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