Q.If \(\cfrac{a}{b + c} = \cfrac{b}{c + a} = \cfrac{c}{a + b}\) and \(a + b + c \ne 0\), then prove that \(a = b = c\).

\(\cfrac{a}{b + c} = \cfrac{b}{c + a} = \cfrac{c}{a + b}\) Or, \(\cfrac{a}{b + c} + 1 = \cfrac{b}{c + a} + 1 = \cfrac{c}{a + b} + 1\) [Adding 1 to both sides] Or, \(\cfrac{a + b + c}{b + c} = \cfrac{b + c + a}{c + a} = \cfrac{c + a + b}{a + b}\) Or, \(\cfrac{1}{b + c} = \cfrac{1}{c + a} = \cfrac{1}{a + b}\) [\(\because a + b + c \ne 0\)]

So, \(b + c = c + a = a + b\) [By reversing the process]

∴ \(b + c = c + a\) ⇒ \(b = a\) Again, \(c + a = a + b\) ⇒ \(c = b\)
∴ \(a = b = c\) (Proved)
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