Q.Find the value of \( \sin^6 \alpha + \cos^6 \alpha + 3\sin^2 \alpha \cos^2 \alpha \).

\(\sin^6 α + \cos^6 α + 3\sin^2 α \cos^2 α\) \(= \sin^6 α + \cos^6 α + 3\sin^2 α \cos^2 α \times 1\) \(= (\sin^2 α)^3 + (\cos^2 α)^3 + 3\sin^2 α \cos^2 α \cdot (\sin^2 α + \cos^2 α)\) \(= (\sin^2 α + \cos^2 α)^3\) \(= 1^3\) \(= 1\)
Similar Questions