Answer: C
Given the equation: \((p+2)x^2 - (p-3)x + 3p - 1 = 0\) Let the roots be \(\alpha\) and \(\beta\), which are equal in magnitude but opposite in sign. So, \(\alpha + \beta = 0\) ⇒ \(-\frac{-(p-3)}{p+2} = 0\) ⇒ \(p - 3 = 0\) ⇒ \(p = 3\)
Given the equation: \((p+2)x^2 - (p-3)x + 3p - 1 = 0\) Let the roots be \(\alpha\) and \(\beta\), which are equal in magnitude but opposite in sign. So, \(\alpha + \beta = 0\) ⇒ \(-\frac{-(p-3)}{p+2} = 0\) ⇒ \(p - 3 = 0\) ⇒ \(p = 3\)
Warning: Undefined array key 26 in /home/u275975018/domains/ganitsarani.in/public_html/en/common/searchfunctions_eng.php on line 431
Fatal error: Uncaught ValueError: substr_count(): Argument #2 ($needle) cannot be empty in /home/u275975018/domains/ganitsarani.in/public_html/en/common/searchfunctions_eng.php:432 Stack trace: #0 /home/u275975018/domains/ganitsarani.in/public_html/en/common/searchfunctions_eng.php(432): substr_count() #1 /home/u275975018/domains/ganitsarani.in/public_html/en/common/searchfunctions_eng.php(389): en_bookarray() #2 /home/u275975018/domains/ganitsarani.in/public_html/en/answer.php(332): en_sortvalue() #3 {main} thrown in /home/u275975018/domains/ganitsarani.in/public_html/en/common/searchfunctions_eng.php on line 432