Q.If \( \csc^2 θ = 2 \cot θ \), then find the value of \( θ \), where \( 0^\circ < θ < 90^\circ \).

\(\csc^2 θ = 2 \cot θ\) i.e., \(1 + \cot^2 θ = 2 \cot θ\) i.e., \(1 + \cot^2 θ - 2 \cot θ = 0\) i.e., \((\cot θ - 1)^2 = 0\) i.e., \(\cot θ - 1 = 0\) i.e., \(\cot θ = 1 = \cot 45^\circ\) [since \(0^\circ < θ < 90^\circ\)] i.e., \(\theta = 45^\circ\)
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