Answer: C
Let the radius of the circle be \(r\) meters. \(\therefore r^2 + r^2 = (4\sqrt{2})^2\) i.e., \(2r^2 = 32\) i.e., \(r^2 = 16\) i.e., \(r = 4\) \(\therefore\) The radius of the circle is 4 meters.
Let the radius of the circle be \(r\) meters. \(\therefore r^2 + r^2 = (4\sqrt{2})^2\) i.e., \(2r^2 = 32\) i.e., \(r^2 = 16\) i.e., \(r = 4\) \(\therefore\) The radius of the circle is 4 meters.