Answer: A
Given: \(3x^2 + (k - 1)x + 9 = 0\) If one root is 3, then: Substitute \(x = 3\): ā \(3 \times 3^2 + (k - 1) \times 3 + 9 = 0\) ā \(27 + 3k - 3 + 9 = 0\) ā \(3k + 33 = 0\) ā \(3k = -33\) ā \(k = -11\)
Given: \(3x^2 + (k - 1)x + 9 = 0\) If one root is 3, then: Substitute \(x = 3\): ā \(3 \times 3^2 + (k - 1) \times 3 + 9 = 0\) ā \(27 + 3k - 3 + 9 = 0\) ā \(3k + 33 = 0\) ā \(3k = -33\) ā \(k = -11\)