Answer: D
Let \(2a = 3b = 4c = k\).
\(\therefore a = \cfrac{k}{2}, b = \cfrac{k}{3}\), and \(c = \cfrac{k}{4}\).
\(\therefore a:b:c = \cfrac{k}{2} : \cfrac{k}{3} : \cfrac{k}{4}\)
Let \(2a = 3b = 4c = k\).
\(\therefore a = \cfrac{k}{2}, b = \cfrac{k}{3}\), and \(c = \cfrac{k}{4}\).
\(\therefore a:b:c = \cfrac{k}{2} : \cfrac{k}{3} : \cfrac{k}{4}\)
\(= \cfrac{1}{2} : \cfrac{1}{3} : \cfrac{1}{4}\)
\(= 6 : 4 : 3\)