Q.If the number of vertices, faces, and edges of a cuboid are \( p \), \( q \), and \( r \) respectively, what is the value of \( \frac{3(p + r)}{2q} \) ? (a) 10 (b) 12 (c) 5 (d) 6
Answer: C
The number of vertices \( p = 8 \), the number of faces \( q = 6 \), and the number of edges \( r = 12 \). \[ \therefore \frac{3(p + r)}{2q} = \frac{3 \times (8 + 12)}{2 \times 6} = \frac{60}{12} = 5 \] Thus, the value of \( \frac{3(p + r)}{2q} \) is 5.
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