Answer: A
\(x^2 + x - 6 = 0\) Or, \(x^2 + 3x - 2x - 6 = 0\) Or, \(x(x + 3) - 2(x + 3) = 0\) Or, \((x + 3)(x - 2) = 0\) ∴ \(x = -3, x = 2\)
\(x^2 + x - 6 = 0\) Or, \(x^2 + 3x - 2x - 6 = 0\) Or, \(x(x + 3) - 2(x + 3) = 0\) Or, \((x + 3)(x - 2) = 0\) ∴ \(x = -3, x = 2\)