Q.What is the value of \(x\) in the equation \(x^2 + x - 6 = 0\)? (a) -3,2 (b) 2,3 (c) -2,3 (d) -2,-3
Answer: A
\(x^2 + x - 6 = 0\) Or, \(x^2 + 3x - 2x - 6 = 0\) Or, \(x(x + 3) - 2(x + 3) = 0\) Or, \((x + 3)(x - 2) = 0\) ∴ \(x = -3, x = 2\)
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