Answer: B
\(p = 100\) rupees, \(t = 8\) years, \(I = 100\) rupees.
\(∴ r = \cfrac{100 \times I}{p \times t} \% = \cfrac{100 \times 100}{100 \times 8} \%\)
\(= \cfrac{25}{2} \% = 12\cfrac{1}{2} \% \).
\(p = 100\) rupees, \(t = 8\) years, \(I = 100\) rupees.
\(∴ r = \cfrac{100 \times I}{p \times t} \% = \cfrac{100 \times 100}{100 \times 8} \%\)
\(= \cfrac{25}{2} \% = 12\cfrac{1}{2} \% \).