Given the equation \(2x^2 + 3x + k = 0\), Comparing it with the standard quadratic equation \(ax^2 + bx + c = 0\), we get: \(a = 2\), \(b = 3\), and \(c = k\) Since the roots are real and equal, ∴ Discriminant \(= 0\) So, \(b^2 - 4ac = 0\) i.e., \(\{3\}^2 - 4 × 2 × k = 0\) Or, \(9 - 8k = 0\) Or, \(-8k = -9\) Or, \(k = \cfrac{9}{8}\) ∴ The value of \(k = \cfrac{9}{8}\) will make the given quadratic equation have real and equal roots.