If \(3x = 4y = 5z\), then \(x:y:z =\) \(20:15:12\).
Let \(3x = 4y = 5z = k\). \(\therefore x = \cfrac{k}{3}, y = \cfrac{k}{4}, z = \cfrac{k}{5}\). \(\therefore x:y:z = \cfrac{k}{3} : \cfrac{k}{4} : \cfrac{k}{5}\). \[ = \cfrac{1}{3} : \cfrac{1}{4} : \cfrac{1}{5} \] \[ = \cfrac{60}{3} : \cfrac{60}{4} : \cfrac{60}{5} \] \[ = 20:15:12 \]