Q.In triangle ABC, a straight line parallel to side BC intersects sides AB and AC at points P and Q respectively. AP = QC, AB = 12 cm, AQ = 2 cm. Find the length of CQ. (a) 4 cm (b) 6 cm (c) 9 cm (d) None of the above
Answer: A
Let \( AP = QC = x \) cm In triangle \( \triangle ABC \), PQ is parallel to BC ∴ \( \frac{AP}{PB} = \frac{AQ}{QC} \) ∴ \( \frac{AP}{AB - AP} = \frac{AQ}{QC} \) i.e., \( \frac{x}{12 - x} = \frac{2}{x} \) ⇒ \( x^2 = 24 - 2x \) ⇒ \( x^2 + 2x - 24 = 0 \) ⇒ \( (x + 6)(x - 4) = 0 \) ∴ \( x = 4 \) [because \( x ≠ -6 \)]
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