Given: \[ x = \frac{2\sqrt{15}}{\sqrt{5} + \sqrt{3}} \] Then, \[ \frac{x}{\sqrt{3}} = \frac{2\sqrt{15}}{\sqrt{3}(\sqrt{5} + \sqrt{3})} = \frac{2\sqrt{5}}{\sqrt{5} + \sqrt{3}} \] So, \[ \frac{x + \sqrt{3}}{x - \sqrt{3}} = \frac{2\sqrt{5} + (\sqrt{5} + \sqrt{3})}{2\sqrt{5} - (\sqrt{5} + \sqrt{3})} = \frac{3\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}} \] Again, \[ \frac{x}{\sqrt{5}} = \frac{2\sqrt{15}}{\sqrt{5}(\sqrt{5} + \sqrt{3})} = \frac{2\sqrt{3}}{\sqrt{5} + \sqrt{3}} \] So, \[ \frac{x + \sqrt{5}}{x - \sqrt{5}} = \frac{2\sqrt{3} + (\sqrt{5} + \sqrt{3})}{2\sqrt{3} - (\sqrt{5} + \sqrt{3})} = \frac{3\sqrt{3} + \sqrt{5}}{\sqrt{3} - \sqrt{5}} = -\frac{3\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}} \] Now, adding both expressions: \[ \frac{x + \sqrt{3}}{x - \sqrt{3}} + \frac{x + \sqrt{5}}{x - \sqrt{5}} = \frac{3\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}} - \frac{3\sqrt{3} + \sqrt{5}}{\sqrt{5} - \sqrt{3}} \] \[ = \frac{(3\sqrt{5} + \sqrt{3}) - (3\sqrt{3} + \sqrt{5})}{\sqrt{5} - \sqrt{3}} = \frac{2\sqrt{5} - 2\sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{2(\sqrt{5} - \sqrt{3})}{\sqrt{5} - \sqrt{3}} = 2 \] Final Answer: \[ \frac{x + \sqrt{3}}{x - \sqrt{3}} + \frac{x + \sqrt{5}}{x - \sqrt{5}} = 2 \]