Answer: B
A and B are joined, intersecting OP at point M. In the right-angled triangle \(\triangle\)BMP: BM\(^2\) = BP\(^2\) − MP\(^2\) = 10\(^2\) − \((\frac{16}{2})^2\) = 100 − 64 = 36 ∴ BM = \(\sqrt{36}\) = 6 cm ∴ Area of triangle \(\triangle\)POB = \(\cfrac{1}{2} \times\) OP \(\times\) BM = \(\cfrac{1}{2} \times 16 \times 6\) square cm = 48 square cm.
A and B are joined, intersecting OP at point M. In the right-angled triangle \(\triangle\)BMP: BM\(^2\) = BP\(^2\) − MP\(^2\) = 10\(^2\) − \((\frac{16}{2})^2\) = 100 − 64 = 36 ∴ BM = \(\sqrt{36}\) = 6 cm ∴ Area of triangle \(\triangle\)POB = \(\cfrac{1}{2} \times\) OP \(\times\) BM = \(\cfrac{1}{2} \times 16 \times 6\) square cm = 48 square cm.