Q.A's speed is 1 meter/second more than B's speed. In a 180-meter race, A finishes 2 seconds earlier than B. What is B's speed in meters per second?

āϧāϰāĻŋ, B-āĻāϰ āĻ—āϤāĻŋāĻŦ⧇āĻ— \(x\) āĻŽāĻŋāϟāĻžāϰ / āϏ⧇āϕ⧇āĻ¨ā§āĻĄ
∴āϏāĻžāϞāĻŽāĻžāϰ āĻ—āϤāĻŋāĻŦ⧇āĻ— \((x+1)\)āĻŽāĻŋāϟāĻžāϰ / āϏ⧇āϕ⧇āĻ¨ā§āĻĄ
∴ \(180\) āĻŽāĻŋāϟāĻžāϰ āϝ⧇āϤ⧇ B-āĻāϰ āϏāĻŽā§Ÿ āϞāĻžāϗ⧇ \(\cfrac{180}{x}\) āϏ⧇āϕ⧇āĻ¨ā§āĻĄ āĻāĻŦāĻ‚ A-āĻāϰ āϏāĻŽā§Ÿ āϞāĻžāϗ⧇ \(\cfrac{180}{x+1}\) āϏ⧇āϕ⧇āĻ¨ā§āĻĄ

āϏ⧁āϤāϰāĻžāĻ‚ āĻĒā§āϰāĻļā§āύāĻžāύ⧁āϏāĻžāϰ⧇, \(\cfrac{180}{x}-\cfrac{180}{x+1}=2\)
āĻŦāĻž, \(\cfrac{180(x+1-x)}{x(x+1)} =2\)
āĻŦāĻž, \(\cfrac{180}{x^2+x}=2 \)
āĻŦāĻž, \(\cfrac{90}{x^2+x}=1 \)
āĻŦāĻž, \(x^2+x=90 \)
āĻŦāĻž, \(x^2+x-90=0 \)
āĻŦāĻž, \(x^2+(10-9)x-90=0 \)
āĻŦāĻž, \(x^2+10x-9x-90=0 \)
āĻŦāĻž, \(x(x+10)-9(x+10)=0 \)
āĻŦāĻž, \((x+10)(x-9)=0\)

∴āĻšā§Ÿ, \((x+10)=0 \)āĻ…āĻĨāĻŦāĻž, \((x-9)=0 \)

āϝāĻ–āύ \((x+10)=0\),āϤāĻ–āύ \(x=-10 \)
[āĻ•āĻŋāĻ¨ā§āϤ⧁ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻ‹āĻŖāĻžāĻ¤ā§āĻŦāĻ• āĻšāϤ⧇ āĻĒāĻžāϰ⧇ āύāĻž ]
āφāĻŦāĻžāϰ āϝāĻ–āύ \((x-9)=0\),āϤāĻ–āύ, \(x=9\)
∴ B-āĻāϰ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻĒā§āϰāϤāĻŋ āϏ⧇āϕ⧇āĻ¨ā§āĻĄā§‡ \(9\) āĻŽāĻŋāϟāĻžāϰ āĨ¤ - translate in english
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