Answer: A
OQ\(^2\) + PQ\(^2\) = OP\(^2\)
or, \(5^2 + PQ^2 = 13^2\)
or, \(PQ^2 = 169 - 25\)
or, \(PQ = 12\)
The area of \(\triangle OPQ = \cfrac{1}{2} \times 12 \times 5\) square cm.
= 30 square cm
∴ The area of \(PQOR = 2 \times \triangle OPQ\)
= \(2 \times 30\) square cm = \(60\) square cm.
OQ\(^2\) + PQ\(^2\) = OP\(^2\)
or, \(5^2 + PQ^2 = 13^2\)
or, \(PQ^2 = 169 - 25\)
or, \(PQ = 12\)
The area of \(\triangle OPQ = \cfrac{1}{2} \times 12 \times 5\) square cm.
= 30 square cm
∴ The area of \(PQOR = 2 \times \triangle OPQ\)
= \(2 \times 30\) square cm = \(60\) square cm.