Q.The radius of a circle with center \(O\) is 5 cm. Point \(P\) is located at a distance of 13 cm from \(O\). From point \(P\), two tangents \(PQ\) and \(PR\) are drawn to the circle. Find the area of the quadrilateral \(PQOR\). (a) \(60\) square cm (b) \(30\) square cm (c) \(120\) square cm (d) \(150\) square cm
Answer: A
OQ\(^2\) + PQ\(^2\) = OP\(^2\)
or, \(5^2 + PQ^2 = 13^2\)
or, \(PQ^2 = 169 - 25\)
or, \(PQ = 12\)
The area of \(\triangle OPQ = \cfrac{1}{2} \times 12 \times 5\) square cm.
= 30 square cm
∴ The area of \(PQOR = 2 \times \triangle OPQ\)
= \(2 \times 30\) square cm = \(60\) square cm.
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