Answer: D
Assume the annual rate of interest is \(x\%\) Interest on ₹850 for 3 years: \[ \frac{850 \times 3 \times x}{100} = \frac{51x}{2} \text{ rupees} \] Interest on ₹1250 for 4 years: \[ \frac{1250 \times 4 \times x}{100} = 50x \text{ rupees} \] Therefore, \[ \frac{51x}{2} + 50x = 302 \] Or, \[ \frac{151x}{2} = 302 \] Solving, \[ x = 302 \times \frac{2}{151} = 4 \]
Assume the annual rate of interest is \(x\%\) Interest on ₹850 for 3 years: \[ \frac{850 \times 3 \times x}{100} = \frac{51x}{2} \text{ rupees} \] Interest on ₹1250 for 4 years: \[ \frac{1250 \times 4 \times x}{100} = 50x \text{ rupees} \] Therefore, \[ \frac{51x}{2} + 50x = 302 \] Or, \[ \frac{151x}{2} = 302 \] Solving, \[ x = 302 \times \frac{2}{151} = 4 \]