\(a \propto b\) \(\therefore a = k_1 b\) [where \( k_1 \) is a nonzero proportional constant] \(b \propto \cfrac{1}{c}\) \(\therefore b = \cfrac{k_2}{c}\) [where \( k_2 \) is a nonzero proportional constant] \(c \propto d\) \(\therefore c = k_3 d\) [where \( k_3 \) is a nonzero proportional constant] Now, \[ a = k_1 b = \cfrac{k_1 k_2}{c} = \cfrac{k_1 k_2}{k_3 d} \] \[ ad = \cfrac{k_1 k_2}{k_3} = \text{constant} \quad [\text{since } k_1, k_2, k_3 \text{ are constants}] \] \(\therefore a \propto \cfrac{1}{d}\), meaning \( a \) and \( d \) are inversely proportional.