Volume of the rectangular block = \(11 \times 9 \times 6\) cubic cm Radius of each coin = \(\cfrac{3}{2}\) cm ∴ Volume of each coin = \(\pi \left(\cfrac{3}{2}\right)^2 \times \cfrac{1}{4}\) cubic cm = \(\cfrac{22}{7} \times \cfrac{3 \times 3}{2 \times 2} \times \cfrac{1}{4}\) cubic cm Let \(x\) be the number of coins that can be made. Then, \(\cfrac{22}{7} \times \cfrac{3 \times 3}{2 \times 2} \times \cfrac{1}{4} \times x = 11 \times 9 \times 6\) Solving, \(x = \cfrac{11 \times 9 \times 6 \times 7 \times 2 \times 2 \times 4}{22 \times 2 \times 3 \times 3} = 336\) ∴ 336 coins can be made from the block.