Q.A solid rod has a length of \( h \) meters and a diameter of \( r \) meters. It is melted to form 6 spheres, each with a radius of \( r \) meters. Determine the relationship between \( h \) and \( r \).

The volume of the solid rod \[ = \pi \left(\cfrac{r}{2}\right)^2 h \text{ cubic meters} \] The volume of each sphere \[ = \cfrac{4}{3} \pi r^3 \text{ cubic units} \] According to the question, \[ \pi \left(\cfrac{r}{2}\right)^2 h = 6 \times \cfrac{4}{3} \pi r^3 \] \[ \cfrac{r^2 h}{4} = 8 r^3 \] \[ h = 32r \]
Similar Questions