Here’s the English translation of the full solution: --- Let the inner radius of the pipe be \( r \) cm and the outer radius be \( R \) cm. Given height \( h = 14 \) cm According to the question: \[ 2\pi Rh - 2\pi rh = 44 \Rightarrow 2\pi h(R - r) = 44 \Rightarrow 2 × \frac{22}{7} × 14 (R - r) = 44 \Rightarrow R - r = \frac{1}{2} \quad \text{——— (i)} \] Also, \[ \pi R^2h - \pi r^2h = 99 \Rightarrow \pi h(R^2 - r^2) = 99 \Rightarrow \frac{22}{7} × 14 (R + r)(R - r) = 99 \Rightarrow 44 × (R + r) × \frac{1}{2} = 99 \Rightarrow R + r = \frac{9}{2} \quad \text{——— (ii)} \] Adding equations (i) and (ii): \[ (R - r) + (R + r) = \frac{1}{2} + \frac{9}{2} \Rightarrow 2R = \frac{10}{2} = 5 \Rightarrow R = \frac{5}{2} = 2.5 \] Substituting \( R = 2.5 \) into equation (ii): \[ R + r = \frac{9}{2} \Rightarrow 2.5 + r = 4.5 \Rightarrow r = 2 \] --- Therefore, the outer radius of the pipe is 2.5 cm and the inner radius is 2 cm.