Q.If \(O\) is the circumcenter of \(∆ABC\) and \(\angle\)OAB = 50°, then \(\angle\)ACB = (a) 50° (b) 100° (c) 40° (d) 80°
Answer: C
∵ \(OA = OB\), as both are radii of the circle.
∴ \(\angle\)OAB = \(\angle\)OBA = 50°
∴ \(\angle\)AOB = 180° - (50° + 50°) = 80°
Again, the inscribed angle \(\angle\)ACB subtended by arc AB of the circle
= \(\cfrac{1}{2}\) × central angle \(\angle\)AOB

= \(\cfrac{1}{2}\) × 80° = 40°.

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