Q.If \(∠A + ∠B = 90°\), then find the value of \(1 + \frac{\tan A}{\tan B}\).

\(1 + \frac{\tan A}{\tan B}\) \(= 1 + \frac{\tan A}{\tan(90^\circ - A)}\) \(= 1 + \frac{\tan A}{\cot A}\) \(= 1 + \tan^2 A\) \(= \sec^2 A\)
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