Given: \(x = a\sec\theta\) \(\Rightarrow \sec\theta = \frac{x}{a}\) Also, \(y = b\tan\theta\) \(\Rightarrow \tan\theta = \frac{y}{b}\) We know that: \(\sec^2\theta - \tan^2\theta = 1\) Substituting the values: \[ \left(\frac{x}{a}\right)^2 - \left(\frac{y}{b}\right)^2 = 1 \Rightarrow \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] Therefore, the relation between \(x\) and \(y\) eliminating \(\theta\) is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]