Q.In right-angled triangle ABC, ∠ABC = 90°, AB = 3 cm, BC = 4 cm, and from point B, a perpendicular BD is drawn to side AC, meeting AC at point D. Find the length of BD.

In right-angled triangle ∆ABC, AC² = AB² + BC² = 3² + 4² = 9 + 16 = 25 So, AC = √25 = 5 In right-angled ∆ABC, if the base is BC, then the height is AB Again, if the base is AC, then the height is BD ∴ (½) × BC × AB = (½) × AC × BD ⇒ (½) × 4 × 3 = (½) × 5 × BD ⇒ BD = 12⁄5 = 2.4 cm (Answer)
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