Q.If \(\cfrac{x-3y}{2y}=\cfrac{6x-5y}{5x}\), then what is the value of \(x:y\)? (a) 5:1 or 2:5 (b) 1:5 or 2:5 (c) 1:5 or 5:2 (d) None of the above
Answer: A
\(\cfrac{x-3y}{2y}=\cfrac{6x-5y}{5x}\) Or, \(5x^2 - 15xy = 12xy - 10y^2\) Or, \(5x^2 - 15xy - 12xy + 10y^2 = 0\) Or, \(5x^2 - 27xy + 10y^2 = 0\) Or, \(5x^2 - 25xy - 2xy + 10y^2 = 0\) Or, \(5x(x - 5y) - 2y(x - 5y) = 0\) Or, \((x - 5y)(5x - 2y) = 0\) ∴ Either, \(x - 5y = 0\) Or, \(x = 5y\) Or, \(\cfrac{x}{y} = 5\) Or, \(x : y = 5 : 1\) Or, \(5x - 2y = 0\) Or, \(5x = 2y\) Or, \(\cfrac{x}{y} = \cfrac{2}{5}\) Or, \(x : y = 2 : 5\) ∴ \(x : y = 5 : 1\) or \(2 : 5\)
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