Let the height of the cylinder be \( h = 3r \) units and the base radius be \( r \) units. \[ \therefore \text{According to the question, } \pi r^2 \times 3r = 1029\pi \] \[ \Rightarrow 3r^3 = 1029 \] \[ \Rightarrow r^3 = 343 \] \[ \Rightarrow r = 7 \] Now, The total surface area of the cylinder = \( 2\pi r(r + h) \) square cm \[ = 2 \times \frac{22}{7} \times r(r + 3r) \text{ square cm} \] \[ = 2 \times \frac{22}{7} \times 7 \times 4 \times 7 \text{ square cm} \] \[ = 1232 \text{ square cm} \] (Answer)