Let the slant height, radius, and height of the tent be \(l\) meters, \(r\) meters, and \(h\) meters respectively. ∴ According to the question, \(2\pi r = 37\frac{5}{7}\) Or, \(2 \times \frac{22}{7} \cdot r = \frac{264}{7}\) Or, \(r = \frac{264 \times 7}{7 \times 2 \times 22}\) Or, \(r = 6\) Again, according to the question, \(\pi r l = 188\frac{4}{7}\) Or, \(\frac{22}{7} \times 6 \times l = \frac{1320}{7}\) Or, \(l = \frac{1320}{\frac{22}{7} \times 6} = 10\) Again, \(h^2 = l^2 - r^2\) Or, \(h^2 = 10^2 - 6^2\) Or, \(h^2 = 100 - 36 = 64\) Or, \(h = \sqrt{64} = 8\) ∴ The slant height, radius, and height of the tent are 10 meters, 6 meters, and 8 meters respectively.