Let the radius of the base of the right circular cylinder be \(r\) meters and the height be \(h\) meters. Curved surface area: \(2\pi r h = 264 \) ———(i) Volume: \(\pi r^2 h = 924 \) ———(ii) Dividing equation (ii) by equation (i), we get: \(\frac{\pi r^2 h}{2\pi r h} = \frac{924}{264}\) ⇒ \(\frac{r}{2} = \frac{7}{2}\) ⇒ \(r = 7\) ∴ The radius of the base of the cylinder is 7 meters.