Q.If \(\tan(\theta + 15^\circ) = \sqrt{3}\), then what is the value of \(\sin \theta\)?

\(\tan(\theta + 15^\circ) = \sqrt{3}\) ⇒ \(\tan(\theta + 15^\circ) = \tan 60^\circ\) ⇒ \(\theta + 15^\circ = 60^\circ\) ⇒ \(\theta = 60^\circ - 15^\circ = 45^\circ\) \[ \therefore \sin \theta = \sin 45^\circ = \frac{1}{\sqrt{2}} \quad \text{(Answer)} \]
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