Q.Given \(x \propto \frac{1}{y}\), When \(y = 10\), \(x = 5\) So, \(x = \frac{k}{y} = \frac{50}{y}\) When \(y = 5\), \(x = \frac{50}{5} = 10\)

\(x \propto \frac{1}{y}\) or, \(x = \frac{k}{y}\) [where \(k\) is a non-zero constant] Substituting \(y = 10\) and \(x = 5\) into the equation \(x = \frac{k}{y}\), we get: \(5 = \frac{k}{10}\) or, \(k = 50\) Now, substituting \(y = 5\) and \(k = 50\) into the equation \(x = \frac{k}{y}\), we get: \(x = \frac{50}{5} = 10\) \(\therefore\) the value of \(x\) will be 5.
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