Q.If \(\cfrac{x}{y} \propto (x+y)\) and \(\cfrac{y}{x} \propto (x-y)\), then show that \(x^2 - y^2\) is a constant.

\(\cfrac{x}{y} \propto x+y\)
Or, \(\cfrac{x}{y} = k_1(x + y)\) [\(k_1\) is a nonzero constant]
\(\cfrac{y}{x} \propto x-y\)
Or, \(\cfrac{y}{x} = k_2(x - y)\) [\(k_2\) is a nonzero constant]

\(\therefore k_1(x + y) k_2(x - y) = \cfrac{x}{y} \times \cfrac{y}{x}\)
Or, \(k_1 k_2 (x^2 - y^2) = 1\)
Or, \(x^2 - y^2 = \cfrac{1}{k_1 k_2} =\) constant (\(\because k_1, k_2\) are constants) (Proved)
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