Answer: A
\[ (x^2 + y^2) \propto (x^2 - y^2) \Rightarrow (x^2 + y^2) = k(x^2 - y^2) \quad [k \text{ is a non-zero constant}] \Rightarrow x^2 + y^2 = kx^2 - ky^2 \Rightarrow x^2 - kx^2 = -ky^2 - y^2 \Rightarrow x^2(1 - k) = y^2(-k - 1) \Rightarrow \frac{x^2}{y^2} = \frac{-k - 1}{1 - k} \Rightarrow \frac{x^2}{y^2} = \frac{k + 1}{k - 1} \Rightarrow \frac{x}{y} = \sqrt{\frac{k + 1}{k - 1}} = \text{constant} \therefore x \propto y \]
\[ (x^2 + y^2) \propto (x^2 - y^2) \Rightarrow (x^2 + y^2) = k(x^2 - y^2) \quad [k \text{ is a non-zero constant}] \Rightarrow x^2 + y^2 = kx^2 - ky^2 \Rightarrow x^2 - kx^2 = -ky^2 - y^2 \Rightarrow x^2(1 - k) = y^2(-k - 1) \Rightarrow \frac{x^2}{y^2} = \frac{-k - 1}{1 - k} \Rightarrow \frac{x^2}{y^2} = \frac{k + 1}{k - 1} \Rightarrow \frac{x}{y} = \sqrt{\frac{k + 1}{k - 1}} = \text{constant} \therefore x \propto y \]