Answer: D
The current price of the machine is ₹2P. If the price decreases at a rate of 2r% per year, then after 2n years, the price of the machine will be:
\(=2P\left(1-\cfrac{2r}{100}\right)^{2n}\) rupees
\(=2P\left(1-\cfrac{r}{50}\right)^{2n}\) rupees
The current price of the machine is ₹2P. If the price decreases at a rate of 2r% per year, then after 2n years, the price of the machine will be:
\(=2P\left(1-\cfrac{2r}{100}\right)^{2n}\) rupees
\(=2P\left(1-\cfrac{r}{50}\right)^{2n}\) rupees