Q.The current price of a machine is rupees 2P, and if its price decreases by 2r% each year, then after 2n years, the price of the machine will be: (a) \(P\left(1-\cfrac{r}{100}\right)^n\) (b) \(2P\left(1-\cfrac{r}{50}\right)^n\) (c) \(P\left(1-\cfrac{r}{50}\right)^{2n}\) (d) \(2P\left(1-\cfrac{r}{50}\right)^{2n}\)
Answer: D
The current price of the machine is ₹2P. If the price decreases at a rate of 2r% per year, then after 2n years, the price of the machine will be:
\(=2P\left(1-\cfrac{2r}{100}\right)^{2n}\) rupees
\(=2P\left(1-\cfrac{r}{50}\right)^{2n}\) rupees
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