Given: \[ 5 \sin^2\theta + 4 \cos^2\theta = \frac{9}{2} \] Multiply both sides by 2: \[ 2(5 \sin^2\theta + 4 \cos^2\theta) = 9 \Rightarrow 10 \sin^2\theta + 8 \cos^2\theta = 9(\sin^2\theta + \cos^2\theta) \] Since \(\sin^2\theta + \cos^2\theta = 1\): \[ 10 \sin^2\theta + 8 \cos^2\theta = 9 \sin^2\theta + 9 \cos^2\theta \Rightarrow 10 \sin^2\theta - 9 \sin^2\theta = 9 \cos^2\theta - 8 \cos^2\theta \Rightarrow \sin^2\theta = \cos^2\theta \] Divide both sides by \(\cos^2\theta\): \[ \frac{\sin^2\theta}{\cos^2\theta} = 1 \Rightarrow \tan^2\theta = 1 \Rightarrow \tan\theta = 1 \quad (\text{since } 0^\circ < \theta < 90^\circ) \] (Answer)