Q.Find the mode of the following frequency distribution: | Class Interval | 50–59 | 60–69 | 70–79 | 80–89 | 90–99 | 100–109 | |----------------|--------|--------|--------|--------|--------|----------| | Frequency | 5 | 20 | 40 | 50 | 30 | 6 |

The given frequency distribution is in inclusive form. The table is converted into exclusive class boundaries:
Class Boundaries Frequency
49.5–59.5 5
59.5–69.5 20
69.5–79.5 40
79.5–89.5 50
89.5–99.5 30
99.5–109.5 6
The modal class from the above distribution is \(79.5–89.5\) ∴ Mode is calculated using the formula: \[ \text{Mode} = l + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h \] Where: - \(l = 79.5\) = lower boundary of modal class - \(f_1 = 50\) = frequency of modal class - \(f_0 = 40\) = frequency of preceding class - \(f_2 = 30\) = frequency of succeeding class - \(h = 10\) = class width \[ = 79.5 + \frac{50 - 40}{2 \times 50 - 40 - 30} \times 10 = 79.5 + \frac{10}{30} \times 10 = 79.5 + \frac{100}{30} = 79.5 + 3.33 = 82.83 \text{ (approx.)} \]
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