Q.A is in joint variation with B and C². If A = 144 when B = 4 and C = 3, then what is the value of the constant of variation? (a) \(\frac{1}{4}\) (b) \(\frac{1}{2}\) (c) \(\frac{1}{3}\) (d) \(\frac{1}{5}\)
Answer: A
\(BC^2 \propto A\) Or, \(BC^2 = Ak\) Or, \(4 \cdot 3^2 = 144k\) Or, \(144k = 36\) Or, \(k = \frac{36}{144} = \frac{1}{4}\)
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