Three equal circles with centers at A, B, and C are externally tangent to each other. We need to prove that AB = BC = CA. Proof: Since the three circles touch each other externally, the straight line joining the centers of any two circles equals the sum of their radii. Let the radius of each circle be \(r\). ∴ AB = 2r, BC = 2r, and CA = 2r ∴ AB = BC = CA (Proved)