Q.Given \(x = 3 + \sqrt{3}\) and \(y = 6\), find the value of \((x + y)^2\).

Given: \[ x + y = 3 + \sqrt{3} + 6 = 9 + \sqrt{3} \] \[ \therefore (x + y)^2 = (9 + \sqrt{3})^2 = 81 + 3 + 2 \cdot 9 \cdot \sqrt{3} = 84 + 18\sqrt{3} \]
Similar Questions