Q.If \(x^2 + y^2 - 4x - 6y + 13 = 0\), then what is the value of \((x + y) : (y - x)\)?

Given: \(x^2 + y^2 - 4x - 6y + 13 = 0\) \(\Rightarrow x^2 - 4x + 4 + y^2 - 6y + 9 = 0\) \(\Rightarrow (x - 2)^2 + (y - 3)^2 = 0\) \(\Rightarrow x = 2, y = 3\) \(\Rightarrow (x + y) : (y - x) = 5 : 1\)
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