Answer: D
If OD ⊥ PQ, then D is the midpoint of PQ. PD = ½ × PQ = 8 cm. Therefore, in the right-angled triangle △OPD: OD² = OP² − PD² i.e., OD² = 10² − 8² = 100 − 64 = 36 ∴ OD = 6 cm.
If OD ⊥ PQ, then D is the midpoint of PQ. PD = ½ × PQ = 8 cm. Therefore, in the right-angled triangle △OPD: OD² = OP² − PD² i.e., OD² = 10² − 8² = 100 − 64 = 36 ∴ OD = 6 cm.