Q.A circle with center O has a radius of 10 cm. PQ is a chord with a length of 16 cm. The length of the perpendicular drawn from O to PQ is — (a) 8 cm (b) 10 cm (c) 16 cm (d) 6 cm
Answer: D
If OD ⊥ PQ, then D is the midpoint of PQ. PD = ½ × PQ = 8 cm. Therefore, in the right-angled triangle △OPD: OD² = OP² − PD² i.e., OD² = 10² − 8² = 100 − 64 = 36 ∴ OD = 6 cm.
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