Q.Determine the combined mean using the step deviation method from the following data:
Class Interval0 - 1010 - 2020 - 3030 - 4040 - 5050 - 60
Frequency7561282


Taking \(a = 25\) and \(h = 10\), we obtain:
Class Interval Frequency \((f_i )\) Class Midpoint \((x_i)\) \(u_i = \cfrac{x_i - a}{10}\) \(f_i u_i\)
0-10 7 5 -2 -14
10-20 5 15 -1 -5
20-306 25 0 0
30-40 12 35 1 12
40-50 8 45 2 16
50-60 2 55 3 6
Total \(ÎĢf_i = 40 \) \(ÎĢf_i u_i = 15\)


Using the step deviation method, the required mean is:
\(= a + h \times \cfrac{ÎĢf_i u_i}{ÎĢf_i} \)
\(= 25 + 10 \times \cfrac{15}{40}\)
\(= 25 + 3.75 = 28.75\) (Answer).
(Proved).
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